When the speed of the car increases by 13.3 percent, the breaking distance increases by 13.3 percent as well.
<h3>Increase in the distance of the car</h3>
The increase in the distance of the car is calculated as follows;
v = d/t
where;
d is distance
t is time
v is speed
Distance and speed are directly proportional, thus, when the speed of the car increases by 13.3 percent, the breaking distance increases by 13.3 percent as well.
According to another source this is what I got <span>0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m ) </span>Hope it helps