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inysia [295]
3 years ago
13

An acorn with a mass of .0300 kg is hanging from a branch in a tree it is 2.50 M off the ground what is the potential energy of

the acorn
0.735 j
0.075 j
1.84 j
0.00j
Physics
2 answers:
Alekssandra [29.7K]3 years ago
5 0
According to another source this is what I got
<span>0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m ) 
</span>Hope it helps
Gennadij [26K]3 years ago
5 0
0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m ) 
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The four basic perceptual characteristics of sound are pitch, loudness, quality and fidelity. Pitch is the perception of a high or low sound, loudness is the intensity of a sound, phase is the increase and decrease in pressure cycle any single vibration, loudness is a quality defined as the intensity of sound energy as it comes in contact with an eardrum or other surface.
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3 years ago
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You take a trip to Oklahoma City. The turnpike between Tulsa and OKC
laiz [17]

speed_{avg} =  \frac{Σ\:distance}{ total\: time}

So, according to the question:

distance = 90 miles

time = 1h 45min + 15 min + 1h = 3h

Therefore:\\ speed_{avg} =  \frac{90}{3} mph \\  = \boxed {30 \: mph}

7 0
2 years ago
A squirrel on a limb near the top of a tree loses its grip on a nut, so that the nut slips away horizontally at a speed of 1.5m/
tatiyna

Answer:

The height of the squirrel  h =113 \  m

Explanation:

From the question we are told that  

    The horizontally speed is v  = 1.5 m/s

    The horizontal  distance d =  7.2 \ m

Generally the the time taken is mathematically represented

      t = \frac{d}{v}

=>   t = \frac{7.2}{1.5}

=>   t = 4.8 \  s

Generally from kinematic equation we have that

     h =  ut + \frac{1}{2} gt^2

Here u  is the initial velocity of nut in the vertical and the value is 0 m/s

     h =  0 * 4.8  + \frac{1}{2} * 9.8 * (4.8)^2

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6 0
3 years ago
Please help me with this Physics question?
Leno4ka [110]

C 82.4 N sorry man if i am wrong but don't even think about reporting my answer

6 0
3 years ago
A sample contains 20 kg of radioactive material. The decay constant of the material is 0.179 per second. If the amount of time t
Nataly [62]

Answer:

Explanation:

Given

N0 = 20kg (original substance)

decay constant λ = 0.179/sec

time t = 300s

We are to find N(t)

Using the formula;

n(t) = N0e^-λt

Substitute the given values

N(t) = 20e^-(0.179)(300)

N(t) = 20e^(-53.7)

N(t) = 20(4.7885)

N(t) =143.055

To know how much of the original material that is active, we will find N(t)/N0 = 143.055/20 = 7.152

About 7 times the original material is still radioactive

4 0
3 years ago
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