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Arlecino [84]
3 years ago
5

The power of the kettle was 2.6 kW

Physics
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

Cp = 4756 [J/kg*°C]

Explanation:

In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.

Q = m*Cp*(T_f - T_i)/t

where:

Q = heat transfer = 2.6 [kW] = 2600[W]

m = mass of the water = 0.8 [kg]

Cp = specific heat of water [J/kg*°C]

T_f  = final temperature of the water = 100 [°C]

T_i = initial temperature of the water = 18 [°C]

t = time = 120 [s]

Now clearing the Cp, we have:

Cp = Q*t/(m*(T_f - T_i))

Now replacing

Cp = (2600*120)/(0.8*(100-18))

Cp = 4756 [J/kg*°C]

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My believe the answer is

A.) or B.)

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<em>This makes sense because we all know in winter the weather is very cold and freezing.</em>

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<em>I feel like this answer is the question, but it could also be an answer, sorry, I'm a little uncertain.</em>

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<em>This answer has nothing to do with the question, plus it is very false, our body heat is not enough to overcome the very cold temperature from outside.</em>

d) Porque la temperatura del aire es igual a la temperatura del cuerpo.

<em>This is false because again our body heat is not even compared to the freezing cold temperatures from the winter.</em>

<em />

<em />

<h2>Well, have a nice rest of the day!</h2><h3>ba baiii!</h3>
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