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mezya [45]
3 years ago
6

Cam y'all please help me with this one

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0
What even is that I have never seen anything like that
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answer is in image attached

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3 years ago
Robert randomly surveyed 10 ninth-grade students at Lincoln High School to determine their favorite color. Of the 10 students su
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he is not wrong 5/10 of people is equal to 50% of people

Step-by-step explanation:

5 0
4 years ago
Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
lisabon 2012 [21]

Given the following functions below,

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}

Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
Marco has a sandbox that is 3 1/2 feet long, 1/2 feet wide, and foot deep. How
dybincka [34]
I don’t know the depth but I can tell you that you need to multiply everything using the formula v=l*w*h. So v=3.5*0.5*x
4 0
3 years ago
PLEASEHELP!
denis-greek [22]
You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5

100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10

6 0
3 years ago
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