Pleasee Help !!!!

A basketball player shoots a basketball that reaches a height above 15 feet before landing back on the ground exactly after 7 se

Papessa [141]

Answer:

I and IV

Step-by-step explanation:

Since the height of the basketball reaches above 15 feet, hence the maximum of the function should be greater than 15 feet. Also at 7 seconds, the ball is on the ground, hence f(7) = 0 feet

The maximum of a function is at x = -b/2a

i) f(x) = -(x-3)² + 16 = -(x² - 6x + 9) + 16 = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 16 = 16 > 15

Also f(7) = - (7 - 3)² + 16 = 0

Hence this option is correct

ii) f(x) = -x² + 8x - 7

The maximum of a function is at x = -b/2a = -8 / 2(-1) = 4

f(4) = -4² + 8(4) - 7 = 9 < 15 not correct

Also f(7) = - 7² + 8(7) - 7 = 0

Hence this option is not correct since the maximum f(4) = 9 < 15

iii) f(x) = -(x-3)² + 14 = -(x² - 6x + 9) + 14 = -x² + 6x + 5

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3-3)² + 14 = 14 < 15

Also f(7) = - (7 - 3)² + 14 = -2

Hence this option is not correct since the maximum f(4) = 9 < 15 and f(7) ≠ 0

iv)f(x) = -x² + 6x + 7

The maximum of a function is at x = -b/2a = -6 / 2(-1) = 3

f(3) = -(3)² + 6(3) + 7 = 16 > 15

Also f(7) = - (7)² + 6(7) + 7 = 0

Hence this option is correct

3 0

3 years ago

Simplify polynomial

Kay [80]

Answer:

j² - 5j²k - 2

Step-by-step explanation:

3j² - j²k - 6 - 4j²k - 2j² + 4

To simplify this polynomial, we can collect like terms. A term is number(s) or variable(s) that are grouped together by multiplication. <u>Like terms have the same variable and exponent</u>.

We have three groups of like terms:

The j-squares (j²), the j-squared k (j²k) and the constants (no variable).

Remember to include the negatives!

The j-squares are: 3j² ; -2j²

The j-squares k are: - j²k ; - 4j²k

The constants are: - 6 ; 4

Simplify:

3j² - j²k - 6 - 4j²k - 2j² + 4

Rearrange the polynomial by like terms

= (- j²k - 4j²k) + (3j² - 2j²) + (- 6 + 4)

Add or subtract the like terms

= (-5j²k) + (j²) + (-2)

Remove brackets and rearrange so the negative is not first

= j² + - 5j²k + - 2

Simplify where two signs are together. Adding a negative is subtraction.

= j² - 5j²k - 2 Simplified

8 0

3 years ago

Plz Help ASAP! I will mark Brainliest!

Wewaii [24]

If you have a ruler I can how you a faster why you do this

3 0

3 years ago

Read 2 more answers

How to find the sum of an math problem

skelet666 [1.2K]

Answer:

Add and subtract the remaining numbers in the math problem.

3 0

3 years ago

Read 2 more answers

Think about how to find the area of a rectangle. A=LW and a triangle 1/2B*H. Create a problem using each formula.

WITCHER [35]

Given expressions:

Area of a rectangle = L W

Area of a triangle = $\frac{1}{2} B H$

Problem;

Create problems using the formula;

Solution:

Problem 1; Find the area of a rectangle whose length is 10cm and the width is half the size of the length?

Given parameters:

Length of rectangle = 10cm

Width of rectangle = $\frac{1}{2}$ x length = $\frac{1}{2}$ x 10 = 5cm

So, the area of the rectangle = 10cm x 5cm = 50cm²

2. A triangle with a base length of 30cm and a height of 2cm will have an area of what?

Given parameters:

base length = 30cm

height = 2cm

Solution:

Area of a triangle = $\frac{1}{2}$ x b x h

Area of a triangle = $\frac{1}{2}$ x 30 x 2 = 30cm²

The area of the triangle will be 30cm²

6 0

3 years ago