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Helen [10]
3 years ago
9

Start with the top figure. Which transformation was used to create the pattern?

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

GM2-7: Predict and communicate the results of translations, reflections, and rotations on plane shapes.

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Someone please help with this question for brainliest !!!!:)
N76 [4]

Answer:

d)

Step-by-step explanation:

the polynomial remainder theorem states that the remainder of the division of a polynomial f(x) by a linear polynomial x-r is equal to f(r). In particular, x-r is a divisor (that means a factor) of f(x), if and only if f(r)=0.

our r here is -1 to get x + 1.

f(-1) = 2×(-1)³ + 5×(-1)² - -1 - 6 = -2 + 5 + 1 - 6 = -2

the remainder is -2.

and since the remainder is <> 0, the binomial cannot be a factor.

8 0
3 years ago
A circular table has a diameter of 48". The table can be enlarged by inserting two rectangular leaves, each 18" wide and 48" lon
lukranit [14]
48 x 18 = 864

864 x 2 = 1728

1728 sq in

6 0
4 years ago
Read 2 more answers
Suzanna need a borad that is a least 3.5 meters long.Is the board long enogh
Vlad1618 [11]

Answer:

sweet god yes it is unless she 12 feet tall then no

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP.
ohaa [14]
I hope you're reading this because I didn't answer your question.
6 0
4 years ago
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
4 years ago
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