3 years ago

Find the product of the solutions of this equation 2x^2+26x+156=0

Mathematics

1 answer:

NARA [144]3 years ago

7 0

Check the attached file for the answer.

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9.2 Multiplying and Factoring Polynomials 8m ( m+6 )

poizon [28]

You would multiply 8m by m and 6 separately. it would be 8m^2 + 48m

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3 years ago

The left and right page numbers of an open book are two consecutive integers whose sum is 321

PIT_PIT [208]

Answer:

160,160

Step-by-step explanation:

let the first page be X

second one be x+1

x+x+1=321

2x=320

x= 320÷2=160

pages 160 161

6 0

3 years ago

Sarah has $18.00 and she earns $7.25 an hour at work. what’s the equations

BigorU [14]

Answer:

y = 7.25x + 18

Step-by-step explanation:

18 is the base. so it goes last.

7.25 is the amount being raised per a certain amount (hours) so its 7.25x

6 0

3 years ago

A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes

marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

$V = s^2h = 5324$

$h = 5324 / s^2$

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top $s^2$

Side area 4sh

Total surface area $A = s^2 + 4sh$

We can substitute $h = 5324 / s^2$

$A = s^2 + 4s\frac{5324}{s^2}$

$A = s^2 + 21296/s$

To find the minimum of this function, we can take the first derivative, and set it to 0

$A' = 2s - 21296/s^2 = 0$

$2s = 21296/s^2$

$s^3 = 10648$

$s = \sqrt[3]{10648} = 22$

$h = 5324 / s^2 = 5324 / 22^2 = 11$

4 0

3 years ago

The width of a rectangular swimming pool is 16ft. The diagonal of the swimming pool is 34 ft. What is the length of the swimming

kobusy [5.1K]

The length of the swimming pool is 30 ft

5 0

3 years ago

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