Question

A circle with the equation (x + 6)2 + (y + 3)2 = 16 is reflected over the line x = 2.

Answer 1

Answer: $(x-10)^{2}+(y+3)^{2}=16$

Step-by-step explanation:

We know the center of the original circle is (-6, -3). After reflecting this over the line x=2, the new center is now (10, -3).

Thus, the equation of the circle is $(x-10)^{2}+(y+3)^{2}=16$.