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3 years ago

I need help with this.

Mathematics

1 answer:

alekssr [168]3 years ago

8 0

Answer:

x=7

Step-by-step explanation:

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Container A is cylinder with a radius of 10 units and a height of 10 units. A right cone has been carved from its base and has a

sergij07 [2.7K]

Answer:

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

From the information given,

Height = 10 units

Radius = 10 units

Volume = π × 10² × 10

The formula for determining the volume of a cone is expressed as

Volume = 1/3πr²h

Height = 10 units

Base = 10 units

Volume = 1/3 × π × 10² × 10

Since the cone has been carved from the cylinder, the statement that derives the formula to find the volume of container B is

π × 10² × 10 - 1/3 × π × 10² × 10

7 0

3 years ago

Which strategy can be used to solve this problem? Denzel can paint 12 tiles in an hour. How many tiles can Denzel paint in 4 1/2

ahrayia [7]

12 tiles multiplied by 4.5 house equals 54 tiles

8 0

3 years ago

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What is the mass of 8.65x 10^23 molecules of N2Cl4?

ArbitrLikvidat [17]

Answer:

8.6E23

Step-by-step explanation:

8 0

3 years ago

What is the solution to this equation x/5=25

amid [387]

Answer:

x = 125

Step-by-step explanation:

Given

$\frac{x}{5}$ = 25

Multiply both sides by 5 to clear the fraction

x = 5 × 25 = 125

x = 125

6 0

3 years ago

Read 2 more answers

What is the equation of a line that passes through the points (-3, 4) and (2,8)?

ziro4ka [17]

Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting the points (-3,4) and (2,8) in the above formula, we get;

$m=\frac{8-4}{2+3}$

$m=\frac{4}{5}$

Thus, the slope of the line is $m=\frac{4}{5}$

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting the point (-3,4) and $m=\frac{4}{5}$ in the above formula, we have;

$y-4=\frac{4}{5}(x+3)$

$y-4=\frac{4}{5}x+\frac{12}{5}$

$y=\frac{4}{5}x+\frac{12}{5}+4$

$y=\frac{4}{5}x+\frac{32}{5}$

Thus, the equation of the line is $y=\frac{4}{5}x+\frac{32}{5}$

6 0

3 years ago