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Bumek [7]
3 years ago
8

Please help me on my problem! show me work (if you can, I mean not trying to sound rude)

Mathematics
1 answer:
faltersainse [42]3 years ago
7 0
Divide 436.8 by 62.08


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Variable y varies directly with x2, and y = 96 when x = 4.
lakkis [162]
Direct variation is y = kx, where k is the constant of variation.
 But now it says y varies directly with x2 (or 2x), so now the x in the equation is 2x.

The equation is y = k(2x)
 Now you find k.
y = 96 when x = 4.
(96) = k(2*4)
96 = k(8)
k = 12
 
The equation is now y = 12(2x)
To find the value of y when x=2, plug 2 into the equation you made. y = 12(2*2) y = 48
_________________
Now it's with a "quadratic variation," which is the same thing except x is squared.
The equation is y = kx^2
 
But y varies directly with x2 (same thing as 2x), so now it's y = k(2x)^2.
 
Now you find k by substituting y and x values that were given.
y = 180 when x = 6
(180) = k(2*6)^2
180 = k(12)^2
180 = k(144)
k = 1.25
k, 1.25, is the constant of variation.
4 0
3 years ago
GOOD AT MATH!! PLEASE HELPPP
Valentin [98]
It’s B I’m pretty sure
8 0
3 years ago
Read 2 more answers
Consider the function represented by the graph. What is the domain of this function? {x| x >}
Maksim231197 [3]

Answer:

x | x ≥ 0 and x ≤ 8

Step-by-step explanation:

The domain of the function is defined as the possible x values that can be used in this function. Now, taking a look at the given graph, we would find that the line starts from x = 0 and continues taking x values till it reaches x = 0This means that for this function, we are allowed to use x values that are greater than or equal to zero and less than or equal to 8Therefore, the domain is any x value greater than or equal to zero and less than or equal to 8

5 0
3 years ago
I dont know how to do this so hElp
STALIN [3.7K]

Answer:

3.5× c20

#######################

7 0
2 years ago
Read 2 more answers
Answers? Thanks so much in advance for any help :)
LuckyWell [14K]
13. AC=6 

sorry it's just a guess i'm like 99% sure tho
8 0
3 years ago
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