2 years ago

Find the range of the function y= 1/2 x + 3 when the domain is -2, 0, 2, 4

Mathematics

1 answer:

Mrrafil [7]2 years ago

7 0

Answer:

2 3 4 5

Step-by-step explanation:

1/2*-2+3 = 2

1/2*0+3 = 3

1/2*2+3 = 4

1/2*4+3 = 5

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Find the TWO integers whos product is -12 and whose sum is 1<br>

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Answer:

$\rm Numbers = 4 \ and \ -3.$

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

$\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}$