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patriot [66]
3 years ago
10

Find the range of the function y= 1/2 x + 3 when the domain is -2, 0, 2, 4

Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0

Answer:

2 3 4 5

Step-by-step explanation:

1/2*-2+3 = 2

1/2*0+3 = 3

1/2*2+3 = 4

1/2*4+3 = 5

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−30=5(x+1) please simplify this for khan academy. org
brilliants [131]

Answer:

-7 =x

Step-by-step explanation:

−30=5(x+1)

Divide each side by 5

−30/5=5/5 (x+1)

-6 = x+1

Subtract 1 from each side

-6-1 = x+1-1

-7 =x

4 0
3 years ago
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In isosceles triangle GHK below, what is the value of m?
egoroff_w [7]

Answer:

the anwser is b

Step-by-step explanation:

divide 27 by 180 and you get an answer of 54

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3 years ago
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the temperature of the water in Emily's fish tank was 78 degrees F on Sunday the water temperature was changed by -3 on Monday a
SpyIntel [72]

To solve this problem, let us analyze this step by step. The temperature for each day is as follows:

 

Water temperature on Sunday = 78 degrees F

Water temperature on Monday = changed by -3 degrees F

Water temperature on Tuesday = changed by 3 degrees F

 

We can see that the total change of water temperature from Sunday to Tuesday is:

-3 + 3 = 0

Therefore there is zero overall change. There the integer which represents the temperature change is “0”.

 

Since the overall change in water temperature is zero, hence the temperature on Sunday and on Tuesday is similar.

Water temperature on Tuesday = 78 degrees F

8 0
3 years ago
Normal Distribution. Cherry trees in a certain orchard have heights that are normally distributed with mu = 112 inches and sigma
Lubov Fominskaja [6]

Answer:

The probability that a randomly chosen tree is greater than 140 inches is 0.0228.

Step-by-step explanation:

Given : Cherry trees in a certain orchard have heights that are normally distributed with \mu = 112 inches and \sigma = 14 inches.

To find : What is the probability that a randomly chosen tree is greater than 140 inches?

Solution :

Mean - \mu = 112 inches

Standard deviation - \sigma = 14 inches

The z-score formula is given by, Z=\frac{x-\mu}{\sigma}

Now,

P(X>140)=P(\frac{x-\mu}{\sigma}>\frac{140-\mu}{\sigma})

P(X>140)=P(Z>\frac{140-112}{14})

P(X>140)=P(Z>\frac{28}{14})

P(X>140)=P(Z>2)

P(X>140)=1-P(Z

The Z-score value we get is from the Z-table,

P(X>140)=1-0.9772

P(X>140)=0.0228

Therefore, the probability that a randomly chosen tree is greater than 140 inches is 0.0228.

5 0
3 years ago
I need help ASAP !?!?!?!?!!?!?!!??!
s2008m [1.1K]

Answer:

First, do 15/12 then take that and divide by 500!

Step-by-step explanation:

7 0
1 year ago
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