The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
The left side was cut out but x will be on top and 5 in the lower square. The last one is the answer.
Answer:

Step-by-step explanation:
move the terms with
to the left side of the equation:
add 3x to both sides

add 3x and 3x

move all term not containing
to the right side:
add 1 to both sides of the equation


divide each term by 6


simplify the fraction

Answer:
A is the correct answer to the question