Answer:
0.0195 = 1.95% probability that on any given day only John gets homework
Step-by-step explanation:
What is the probability that on any given day only John gets homework?
John has a 65% probability of getting homework.
Paul has a 100 - 80 = 20% probability of not getting homework.
Sonia has a 100 - 85 = 15% probability of not getting homework.
Since these events are independent, the probability is the multiplication.
0.65*0.2*0.15 = 0.0195
0.0195 = 1.95% probability that on any given day only John gets homework
The most reasonable estimate for the height of a two-story house is "15 meters".
The 15 centimeters is not reasonable, it is too small. While the 15 kilometers is not also reasonable since it is too big. Kilometers is used for long distance.
Answer:
The length of the slant height of the square pyramid is 20 in.
Step-by-step explanation:
The lateral surface area of a regular pyramid is the sum of the areas of its lateral faces.
The general formula for the lateral surface area of a regular pyramid is

where
represents the perimeter of the base and
the slant height.
From the information given we know that:
- The lateral surface area of a square pyramid is 440 in².
- The area of the base is 121 in².
And we want to find the the slant height of the pyramid.
For this, we also need to know that the area of a square is given by
, where <em>s</em> is the length of any side and the perimeter of a square is given by
.
Applying the formula for the area of a square we can find the length of the side

The perimeter of the base is

Next, we can apply the formula for the lateral surface area and solve for
the slant height.

The length of the slant height of the square pyramid is 20 in.
25% because even tho its bigger doesnt mean its gonna be correct i am sorry if its wrong not a math person
Answer:

Step-by-step explanation:
The given expression is

Simplify in this context means factorize, which we can do by extracting the common factor 4, which is present in every term of the expression. So, it would result

Remember that to extract a common factor, we just have to divide that factor from each term, and then place it in front of the expression as a factor.