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Julli [10]
3 years ago
15

Kyle and his brother Joel leave a rest stop at the same time traveling in opposite directions. After traveling for 6 hours, they

are 780 miles apart. If Kyle drives 10 miles per hour faster than Joel, how fast was Joel traveling? Kyle and his brother Joel leave a rest stop at the same time traveling in opposite directions. After traveling for 6 hours, they are 780 miles apart. If Kyle drives 10 miles per hour faster than Joel, how fast was Joel traveling?
If anyone could explain, that would be great.
Mathematics
2 answers:
Tom [10]3 years ago
6 0

Answer:

60mph

Step-by-step explanation:

balandron [24]3 years ago
3 0
Kyle's speed is represented by variable k.
Joel's speed is represented by variable j.

Kyle is 10 mph faster.
k= j+10.

Driving in opposite directions after 6 hrs, they are 780 mi apart.
6j + 6k=780

Substitute for k
6j+ 6(j+10)=780
6j+6j+60=780
12j+60=780
12j=720
j=60

Final answer: Joel was travelling 60 mph
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Jemima was arranging 400 packets of biscuits for a sale. She put 52 packets into a basket and displayed 25% of the remaining pac
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2 years ago
Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

  x = 10·cos(θ) -4·cot(θ)

Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

The relevant trig relations are ...

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

If the junction point in the middle of AB is labeled X, then we have ...

  sin(θ) = 4/BX   ⇒   BX = 4/sin(θ)

  cos(θ) = x/XA   ⇒   XA = x/cos(θ)

Then ...

  BX +XA = AB = 10

Substituting for BX and XA using the above relations, we get

  4/sin(θ) +x/cos(θ) = 10

Solving for x gives ...

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6 0
3 years ago
How do I solve this?​
Neporo4naja [7]

Answer:

v = 22

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

\frac{BI}{MO} = \frac{BG}{MP} , substitute values

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3 years ago
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So it seems as if the first problem is asking this:

2 \frac{1}{6} - \frac{11}{15}x. 

If x=0.15, then 11/15*(0.15) is 0.11 or 11/100. 

The second problem is asking:

\frac{x}{4} + \frac{1}{2} = \frac{x}{3} + \frac{1}{6}

To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:

3x+6=4x+2

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Subtract 6 from both sides:
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Multiply by -1 on both sides:
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8 0
3 years ago
Read 2 more answers
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