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strojnjashka [21]
2 years ago
15

500m of fencing is available to make 4 rectangular pens of identical shape. Find the dimensions that maximise the area of each p

en if the plan is: (DIAGRAMS BELLOW)

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:

The answer is "x(\frac{250}{3}-x)"

Step-by-step explanation:

Both points are similar that's why the solution is:

\to \frac{6x+6y=500}{6}\\\\\to x+y=\frac{250}{3}\\\\\to y= \frac{250}{3}-x \\\\\to Area= xy\\\\ \to Area= x(\frac{250}{3}-x)

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Elina [12.6K]
Answer: The average rate of change is 6.
First, plug in each value of <em>t</em> into the function, v(t) to find there coordinate pairs.

v(2) = (2)^2 - (2) + 10
v(2) = 4 + 8
v(2) = 12

v(5) = (5)^2 - (5) + 10
v(5) = 25 + 5
v(5) = 30

You can write these values as coordinate pairs, like so: (2, 12) and (5, 30).
The formula for the average rate of change is A(x) =  \frac{f(x)-(f(a)}{x-a}. When you plug in the values from this particular case, the average rate of change formula becomes A(t) = \frac{30-12}{5-2}, or A(t)= \frac{18}{3}.

Looking at the equation, you can solve for the average rate of change between t = 2 and t = 5, which equals 6.
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3 years ago
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alukav5142 [94]

Answer:

48

Step-by-step explanation:

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8 0
3 years ago
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3 0
3 years ago
Help ASAP! And explain!
stich3 [128]

Answer:

Option (2)

Step-by-step explanation:

Given:

AC is an angle bisector of ∠DAB and ∠DAB

m∠BCA ≅ m∠DCA

m∠BAC ≅ m∠DAC

To Prove:

ΔABC ≅ ΔADC

Solution:

               Statements                                  Reasons

1). m∠BCA ≅ m∠DCA                            1). Given

2). m∠BAC ≅ m∠DAC                           2). Given

3). AC ≅ AC                                            3). Reflexive property

4). ΔABC ≅ ΔADC                                 4). ASA property of congruence

Therefore, Option (2) will be the correct option.

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2 years ago
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