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strojnjashka [21]
2 years ago
15

500m of fencing is available to make 4 rectangular pens of identical shape. Find the dimensions that maximise the area of each p

en if the plan is: (DIAGRAMS BELLOW)

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:

The answer is "x(\frac{250}{3}-x)"

Step-by-step explanation:

Both points are similar that's why the solution is:

\to \frac{6x+6y=500}{6}\\\\\to x+y=\frac{250}{3}\\\\\to y= \frac{250}{3}-x \\\\\to Area= xy\\\\ \to Area= x(\frac{250}{3}-x)

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A right triangle ABC with right angle at B and base BC is drawn. Length of AB is 12, length of BC is 11.5. A similar right trian
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Answer:

Option D is correct.

Length of PQ is 36 unit.

Explanation:

If the measures of two sides in one triangle are proportional to the corresponding sides in the another triangle and their including angles are congruent, then the triangles are similar.

Given: Right angle triangle ABC at B , Length of AB = 12 unit and length of BC = 11.5 unit and in right angle triangle PQR at Q , length of QR = 34.5 unit.

Also it is given that  Angle A is congruent to angle P and angle C is congruent to angle R.

To find the length of QR:

It is given that ΔABC and ΔPQR are Similar triangle

then, by the definition of similar triangle:

\frac{PQ}{AB} = \frac{QR}{BC}

Substitute the value of AB, QR and BC to solve for PQ;

\frac{PQ}{12}=\frac{34.5}{11.5} or

PQ = \frac{34.5 \times 12}{11.5}

On simplify:

PQ = 3 \times 12 = 36

Therefore, the length of side PQ is 36 units.





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