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2 years ago

A (Triangle)ABC is isosceles. AB= 88 and CB = 12x + 4. B x= [?]

Mathematics

1 answer:

CaHeK987 [17]2 years ago

5 0

Answer:

X=7 because 88=12x+4. Simple math gives you x=7

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What is the least common multiple of 6 and 9? 3 18 36 54

kolbaska11 [484]

Answer:

Step-by-step explanation:

3x2= 6

3x3= 9

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3 years ago

What additional information could be used to prove that the triangles are congruent using AAS or ASA? Check all that apply.

lana66690 [7]

ASA Postulate (Angle-Side-Angle)

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

You have that ∠C and ∠Q are congruent. In order to use ASA Postulate, you should have:

1. ∠B and ∠P are congruent and BC=PQ (choice 1)

2. ∠A and ∠T are congruent and AC=TQ (choice 2)

AAS Postulate (Angle-Angle-Side)

If two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

In order to use AAS Postulate, you should have:

1. ∠A and ∠T are congruent and BC=PQ (choice 4);

2. ∠B and ∠P are congruent and AC=TQ;

Answer: correct options are 1, 2, 4.

3 0

3 years ago

Read 2 more answers

Help please Find the area of the following colored regions?

Svet_ta [14]

Answer:

Area = 77.1

Step-by-step explanation:

The are of a right triangle is

$\frac{1}{2} \times base \times height$

our base and height are 6 for both triangles, so we shall find the area of one of the triangles...

$\frac{1}{2} \times 6 \times 6 = 18$

multiply this by 2

$2 \times 18 = 36$

Now find the area of the whole circle

$area = \pi {r}^{2}$

our radius is 6, therefore:

$area = \pi {6}^{2} = 113.1$

Finally, subtract the area of the two triangles from the total are of the circle. The difference left over is our answer

$113.1 - 36 = 77.1$

5 0

3 years ago

Read 2 more answers

I need help, Gonna give brainliest to right answer

Brums [2.3K]

Answer:

s = 7t

Step-by-step explanation:

8 0

2 years ago

Historical data for a local steel manufacturing company shows that the average number of defects per standard sheet of steel is

Yanka [14]

Answer:

Therefore the correct answer is A.) 84.88%

Step-by-step explanation:

i) λ = 2

ii) λ for three units = 2 $\times$ 3 = 6

iii) P(x ≥ 4) = 1 - P(x < 4) = 1 - {P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) }

= 1 - { $\frac{e^{-6}6^{0} }{ 0!} + \frac{e^{-6}6^{1} }{ 1!} + \frac{e^{-6}6^{2} }{ 2!} + \frac{e^{-6}6^{3} }{ 3!}$ }

= 1 - (0.0025 + 0.0149 + 0.0446 + 0.0892)

= 0.8488

Therefore the correct answer is A.) 84.88%

8 0

2 years ago