Answer:
qp is congruent to hg
Step-by-step explanation:
since the given is AAS it has to be angle angle side, you have the angles, r is congruent to i and q is congruent to h, so you need the next sides to be congruent
Answer:
$75 ?
Step-by-step explanation:
If this is wrong super sorry :)
I've answered your other question as well.
Step-by-step explanation:
Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.
Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3
⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab
Substituting a=sin2(x) and b=cos2(x), we have:
sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)
Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:
sin6(x)+cos6(x)=1−3sin2(x)cos2(x)
From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)
Meaning the expression can be rewritten as:
sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)
Answer:
373.8mmHg
Step-by-step explanation:
a =height (in km) above sea level,
the pressure P(a) (in mmHg) is approximated given as
P(a) = 760e–0.13a .
To determine the atmospheric pressure at 5.458 km, then we will input into the equation
P(5.458km) = 760e–0.13a .
= 760e^(-0.13×5.458)
=760e^-(0.70954)
= 760×0.4919
=373.8mmHg
Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg
Based on the points on the graph, the correct matches are:
- A - (-4, -2).
- B - .(2, -4)
- C - (4, -2).
- D - (2, 5)
- E - (-1, 1)
- F - (-5, 0)
- G - (4, 2)
- H - (0, -5)
<h3>How are points located on a graph?</h3>
To find a point, you need to look at the x-axis first and then the y-axis.
Find where the point is located on the x-axis, and then look for where the point intersects with the y-axis point.
For instance, the point A is located at (-4, -2) so look at the -4 point on the x axis, then go down to the -2 point on the y-axis. You'll find point A.
Find out more on the coordinates of points on graphs at brainly.com/question/11337174.
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