The answer is 18 water bottles in a case.. but where did you get the negative nine over nine before your answer
Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
The correct answer is C. 2 3/8 yd.
I hope that helped you! c:
3/4= j-1/2
first to add 1/2 to both sides to solve for j
3/4 + 1/2= j
second you find a common denominator in order to add 3/4 and 1/2, the common denominator would be 4, you would have to change 3/4 at all because the denominator is already 4 but in order to make the denominator of 1/2, 4 you would have to multiply both the denominator and numerator by 2 so
3/4 + 2/4 = 5/4
so 5/4 =j
to check your answer you plug 5/4 in for j
3/4 = 5/4 -1/2
again you need to find a common denominator between 5/4 and 1/2 which again would be 4, and again you wouldn't change 5/4 but you would multiply both the numerator and the denominator of 1/2 so
3/4= 5/4-2/4
5-2= 3 and you would keep the 4 so
5/4 - 2/4 = 3/4
so j = 5/4
