Here , we are given with a circle on cartesian plane , and we need to find the <em>equation of the circle </em>, We are also given that it's centre is at <em>(5,-6) </em>{ From graph } and it's radius is<em> 3 units</em> . Now , as we know, the standard equation of a circle is where <em>(h,k) </em>is the centre of the circle and radius is <em>r</em> . Now , our equation will be ;
<em>This is the required equation of Circle </em>
Or if you want to proceed it further , then you will get <em>x² + y² - 10x + 12y + 50 = 0 </em>
18 divided by 9 = 2
9 = four bunches so 2 x 4 bunches
= bunches
Given:
Right triangle with one angle 45°
To find:
The value of q and r.
Solution:
Opposite to θ = 16
Adjacent to θ = r
Hypotenuse = q
Using trigonometric ratio formula:
The value of tan 45° = 1
Do cross multiplication, we get
r = 16
Using trigonometric ratio formula:
The value of sin 45° = .
Do cross multiplication, we get
The value of r is 16 and the value of q is .