We are given with
dimensions of wheelbarrow = 2ft x 3ft x 1.5 ft
dimensions of truck = 11 ft x 8 ft x 6 ft
The volume of the wheelbarrow is 2(3)(1.5) = 9 ft3
The volume of the truck is 11(8)(6) = 528 ft3
70% of this is
528 ft3 (0.7) = 369.6 ft3
Dividing this by the volume of the wheelbarrow
369.6 ft3 / 9 ft3 = 41.07
He would need to use the wheelbarrow 42 times.
Answer:
3x + 5y = 11 -> y = -3/5x + 11/5
9x + 15y = 33 -> y = -3/5x + 11/5
Answer:
m=3/2
Step-by-step explanation:
Two points are shown
point 1: (0;-3). 4;3. -2-6
point 2: (2;0)



C because you multiply both sides by 5 and get d>20
Answer:
Pascal's Principal- A change in pressure at any point in an enclosed fluid will be transmitted equally to all parts of the fluid.
Real World Example- It could be anything such as, a tire when aired up.