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iragen [17]
3 years ago
8

What was John’s age 4 years ago, if he is y years old now?

Mathematics
1 answer:
n200080 [17]3 years ago
8 0

To find his age 4 years ago, you need to subtract 4 from his current age.

His current age is Y, so his age 4 years ago is: y - 4

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In two or more complete sentences describe whether or not the given relation represents a function.
vichka [17]
To be a function each x-value (input) should have only one y-value (output). Here you can see when x=2 it has an output of either 5 or 1. Therefore, the relation is NOT a function.
4 0
3 years ago
For which color is the difference between the theorectical probability and experimental probability greatest?
Elan Coil [88]

Answer:

The answer is D. Green; The experimental probability is 22.7%, and the theoretical probability is 15%.

5 0
3 years ago
5/7x-4=21<br> solve folve for x
Aleksandr-060686 [28]

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

7*x-4-(21)=0

Solve  :    7x-25 = 0

Add 25 to both sides of the equation :

                     7x = 25

Divide both sides of the equation by 7:

                    x = 25/7 = 3.571

6 0
3 years ago
Read 2 more answers
4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean
Ede4ka [16]

Adding 2 to each value of the random variable X makes a new random variable X+2. Its mean would be

E[X+2]=E[X]+E[2]=E[X]+2

since expectation is linear, and the expected value of a constant is that constant. E[X] is the mean of X, so the new mean would be

E[X+2]=10+2=12

The variance of a random variable X is

V[X]=E[X^2]-E[X]^2

so the variance of X+2 would be

V[X+2]=E[(X+2)^2]-E[X+2]^2

We already know E[X+2]=12, so simplifying above, we get

V[X+2]=E[X^2+4X+4]-12^2

V[X+2]=E[X^2]+4E[X]+4-12^2

V[X+2]=(V[X]+E[X]^2)+4E[X]-140

Standard deviation is the square root of variance, so V[X]=3^2=9.

\implies V[X+2]=(9+10^2)+4(10)-140=9

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of aX+b for a,b\in\mathbb R is

V[aX+b]=a^2V[X]+b^2V[1]

but the variance of a constant is 0. In this case, a=1, so we're left with V[X+2]=V[X], as expected.

5 0
3 years ago
Un carro recorre 784 kilometros en una hora expresar la rapidez en m/sg
9966 [12]

Answer:

217.7777 m/s

Step-by-step explanation:

1km = 1000 metros

784 km = 784*1000 = 784000 metros

1 hora = 3600 segundos

entonces:

784 kilómetros en una hora = 784km/h = 784000m/3600ses

= 217.7777 m /s

es decir que recorre en cada segundo:

217.7777 metros.

Tarea relacionada:

https://brainly.lat/tarea/16056884

4 0
3 years ago
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