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Jobisdone [24]
2 years ago
9

7

Mathematics
1 answer:
elixir [45]2 years ago
8 0

The area of the track will be 78501 m². The area of the track is equal to the area of the circle.

<h3>What is the area?</h3>

The space filled by a flat form or the surface of an item is known as the area.

The number of unit squares that cover the surface of a closed-form is the figure's area. Square meters and other similar units are used to measure area.

The area of the track is found as;

\rm A=\frac{\pi}{4} d^2 \\\\ \rm A=\frac{3.14}{4} (100)^2 \\\\ A=7850 \ m^2

Hence, the area of the track will be 78501 m².

To learn more about the area, refer to the link;

brainly.com/question/11952845

#SPJ1

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A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
4vir4ik [10]

Answer:

There is no question.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A production process is checked periodically by a quality control inspector. the inspector selects simple random samples of 30 f
777dan777 [17]

Answer:

Population Mean = 2.0

Population Standard deviation = 0.03

Step-by-step explanation:

We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.

Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.

Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.

So,   Mean, \mu = \frac{1.9+2.1}{2} = 2.0

Therefore, mean for the population of products produced with this process is 2.

Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.

             z = -1.6449 {from z % table}

We know that z formula is given by ;  

                Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

              -1.6449 = \frac{1.9 - 2.0}{\frac{\sigma}{\sqrt{n} } }     ⇒  \frac{\sigma}{\sqrt{n} }  = \frac{-0.1}{-1.6449}  

                                           ⇒ \sigma = 0.0608 * \sqrt{30}  {as sample size is given 30}

                                           ⇒ \sigma = 0.03 .

Therefore, Standard deviation for the population of products produced with this process is 0.0333.

7 0
3 years ago
Need some help please!!
anygoal [31]

Answer:

The answer to your question is below

Step-by-step explanation:

Domain is the values of x the function can take   D = (-2, 2]

Range is the values of y the function can take     R = [-5, 4]

a) From the graph we got  f(-1) = -5

b) From the graph we got f(0) = -4

c) From the graph we got f(1) = -5

d) From the graph we got f(2) = 4

5 0
3 years ago
Use the rule x + 8 to write a pattern. Begin with x = 0.
Nutka1998 [239]
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