That's a question for arrangement, so we have:
Answer:
D. 7
Step-by-step explanation:
The question is incomplete. Here is a possible complete question
For the given expression, which whole number (w) will make the expression true? 5/6 < w/6
A. 3
B. 4
C. 5
D. 7
Given the inequality expression:
5/6 < w/6
Cross multiply
5×6 < 6×w
30<6w
Divide both sides by 6
30/6 = 6w/6
5<w
Reciprocate both sides(this will change the sense of the inequality)
1/5>1/w
Cross multiply
w > 5×1
w>5
This shows that the value of w is a value greater than 5 but not 5. According to the option, the only value greater than 5 is 7. Hence the whole number (w) that will make the expression true is 7
answer right 2, up 3
any function with the following form is a transformation from f(x) = x²
g(x) = (x – a)² + b
were a moves the function to the right when a is a positive number and to the left when its a negative number, and b moves the function up when b is positive and down when its negative.
then for a=2 positive and b=3 positive, we have
right 2, up 3
6r - 3t = 6 /*8
6r + 8t = - 16 /*3
48r - 24t = 48
48r + 24t = - 48
---------------------- +
96r = 0
r = 0
t = ( -16 + 6r)/8 = - 16/8 = - 2
To convert the improper fraction

into a mixed number, you first want to
divide the numerator (1000)
by the denominator (859)
:

The
quotient, which is 1, will be your whole number part of your mixed number. The
remainder, 141, will become the numerator of the fraction part of your mixed number. The
original denominator of your improper fraction, 859, is still the denominator of your mixed number. So your mixed number form of your improper fraction is:
Your answer is 