Hi there
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 100
R interest rate 0.02
K compounded monthly 12
T time?
We need to solve for t
T=[log (A/p)÷log (1+r/k)]÷k
T=(log(3,000÷100)÷log(1+0.02÷12))÷12
T=170.202 years
So it's a
Hope it helps
Answer:
(i) = 3
(ii) = 20
Step-by-step explanation:
x = 1
y = -2
z = -1
(i) 4x - 3y + 7z
4(1) - 3(-2) + 7(-1)
4 + 6 - 7 = 3
(ii) 2x³ - 6y²z + 3xyz²
2(1)³ - 6(-2)²(-1) + 3(1)(-2)(-1)²
2 + 24 - 6 = 20
It’s y=6x-4y=6x-4y because equals 6
Answer:
-5/2
Step-by-step explanation:
1)
4. ABCDCBA
5. ABCDEDCBA
6. ABCDEFEDCBA
2) 1, 3, 5, 7, 9, 11
3) 19