Answer:
Step-by-step explanation:
=7 (1+11+111+1111......n)
=7/9 (9+99+999+9999....n)
=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)
=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))
=7/9 ((10 (10^n-1)/(10-1))-n)
Answer:
11%
Step-by-step explanation:
1/3 (twix)
1/3 (snicker)
1/3 x 1/3 = 1/9
1/9 = .11
.11 = 11%
Answer:
<h3>Q 17</h3>
a is supplementary with 36 and b is supplementary with 113.
- a = 180 - 36 = 144
- b = 180 - 113 = 67
Correct choice is D
<h3>Q 2</h3>
- LM = 1/2(AB + DC) = 1/2(46 + 125) = 85.5
<h3>Q 3</h3>
Diagonals of a rectangle are congruent
- KM = LN
- 6x + 16 = 49
- 6x = 33
- x = 33/6
- x = 5.5
Correct choice is A
Answer:
45 pictures
Step-by-step explanation:
I did this one too but i don't if they changed the answer good luck I would double check
Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31
2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .
Step-by-step explanation:
1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.
Let x be the number of years starting with 2003 to 2010.
i.e. n=8
and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.
With reference to table we get

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

and

∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)
So, Y= 14640.85 + 937.97×18 = 31524.31
∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31