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2 years ago

Which direction does the decimal point move in when you divide by powers of 10 greater than 0?

Mathematics

2 answers:

Crank2 years ago

8 0

The decimal point will move towards right

4vir4ik [10]2 years ago

7 0

Answer:

the left side is the answer

You might be interested in

Rationalize the denominator of the fraction: √5/√8 - √3

Lana71 [14]

Answer:

Step-by-step explanation:

Remark

The editor must have brackets put around the denominator when there are 2 terms.

That means I think the question is (√5) / (√8 - √3). If this is incorrect, leave a note.

To rationalize the denominator, you must multiply numerator and denominator by the conjugate (√8 + √3).

Solution

√5 * (√8 - √3) / ( (√8 - √3) * (√8 + √3) )

I don't think there is any point in removing the brackets in the numerator. Just leave it.

The denominator is a different matter.

denominator = ( (√8 - √3) * (√8 + √3) )

√8 * √8 = 8

√8 * √3 = √24

- √3 * √8 = - √24

-√3 * √3 = - 3

Take a close look at the 2 middle terms. They cancel out because one of them is plus and the other minus.

What you are left with is 8 - 3 = 5

So the final answer is

√5 * (√8 - √3)

=============

6 0

3 years ago

HELP ALERT ALERT MATH PROBLEM

Lisa [10]

Multiple 15 by 6, the answer is 90 square cm

7 0

3 years ago

Marco has a balance of -$19 in his checking account. He makes a trip to the bank to deposit $368. The next day he purchases a ne

Tomtit [17]

Answer:

His new balance would be $302

7 0

2 years ago

What is m2?<br> What is m<1?

yuradex [85]

Answer:

∠ 2 = 75° , ∠ 1 = 105°

Step-by-step explanation:

∠ 2 and 75° are alternate angles and are congruent , then

∠ 2 = 75°

∠ 1 and ∠ 2 are a linear pair and sum to 180° , that is

∠ 1 + ∠ 2 = 180°

∠ 1 + 75° = 180° ( subtract 75° from both sides )

∠ 1 = 105°

3 0

2 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago

Which direction does the decimal point move in when you divide by powers of 10 greater than 0?￼

Which direction does the decimal point move in when you divide by powers of 10 greater than 0?