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2 years ago

Calculate the missing angle and give a reason for your answer

Mathematics

2 answers:

prisoha [69]2 years ago

7 0

Answer:

h = 56

Step-by-step explanation:

The triangle has 2 congruent sides and is isosceles.

The base angles of an isosceles triangle are congruent, both 62° , then

vertex = 180° - (62 + 62)° = 180° - 124° = 56°

Then

h = 56 ( alternate angles )

Vanyuwa [196]2 years ago

5 0

Step-by-step explanation:

the triangle is an isosceles triangle hence the base angles are equal

sum of angles in a triangle is 180°, therefore, the top angle =180-(62+62)

the top angle =56°

h°= the top angle because alternate angles are equal

hence, h=56°

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What is the algebraic way to solve -10(x-17) = -3 ? Please provide the correct solution :)

suter [353]

Answer:173/10

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

66 bats were sold. Some were sold for $42 each the rest were sold for $30 each. The total sales were$2,460. Write and solve a sy

Phoenix [80]

Answer:

40 bats sold for $42

26 bats sold for $30

Step-by-step explanation:

x + y = 66

42x + 30y = 2460

solve first equation for y and plug in for y in second equation

42x + 30 (66 - x) = 2460

x = 40

y = 66- 40 = 26

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3 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

3 years ago

Write the equation of the circle centered at ( 4 , − 5 ) with radius 18.

Free_Kalibri [48]

Answer:

(x-4)^2 + (y+5)^2 = 324

Step-by-step explanation:

The equation of a circle is given by the equation (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center point of the circle.

Therefore, since the center point of the circle and the radius is given, we can just plug the numbers into the formula:

(x-4)^2 + (y+5)^2 = 18^2

3 0

3 years ago

If the largest angle of a triangle is 120° and it is included between sides of 1.5 and 0.5, then (to the nearest tenth) the larg

12345 [234]

Answer:

1.8 units.

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other and the given angle is the included angle. This means that the angle is formed by the intersection of the two lines. Therefore, cosine rule will be used to calculate the length of the largest side of the triangle. The cosine rule is:

b^2 = a^2 + c^2 - 2*a*c*cos(B).

The question specifies that a=0.5, B=120°, and c=1.5. Plugging in the values:

b^2 = 0.5^2 + 1.5^2 - 2(0.5)(1.5)*cos(120°).

Simplifying gives:

b^2 = 3.25.

Taking square root on the both sides gives b = 1.8 (rounded to the nearest tenth).

This means that the length of the third side is 1.8 units!!!

3 0

3 years ago