The sum of the given expression is 6b^2+8b-15
<h3>Sum of expression</h3>
Given the following expression
(6b^2+5)+(8b-20)
We are to take the sum. On expansion;
6b^2+5 + 8b-20
Collect the like terms
6b^2+8b +5 - 20
6b^2+8b-15
Hence the sum of the given expression is 6b^2+8b-15
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F(-3) = 4(-3) - 3 = -12 - 3 = -15.
H(2) = -5(2) + 7 = -10 + 7 = -3.
F(-3) + H(2) = -15 + -3 = -18.
The solution is -18.
Answer:
912.414
Step-by-step explanation:
The angle
θ
between the directions of motion of planes
θ
=
320
−
200
=
120
∘
The distance
a
traveled by first plane flying at a speed of
150
km/hr
in
3
hrs
a
=
150
⋅
3
=
450
k
m
Similarly, the distance
b
traveled by second plane flying at a speed of
200
km/hr
in
3
hrs
b=
200x3=
600 km
Now, the distance between the planes after 3
hrs will be equal to the side of a triangle opposite to the angle θ=120∘
included by the sides
a
=
450
& b=
600
.
Now, using Cosine rule in the concerned triangle, the distance between the plane after
3
hours is given as
