Answer:
180 children and 175 adults
Step-by-step explanation:
Let it be that the amount of children who visited the park that day was x, the rest was adults. It means the quantity of adults equals 355-x.
The payment from the children is 1.5*x (because each children payed 1.5 dollars, the amount of money from children is the fee from one child multiplied by the quantity of children). The money earned by the park's owners from adults are equal to the fee from one adult multiplied by the quantity 4* (355-x)= 1420 -4x
If we add the money from chilren and adults we get the summary profit of park (it is equal to 970 dollars)
1.5x+ 1420-4x= 970
1420-2.5x= 970
x=180- children
355-180=175adults
Answer:
I believe it would be C, not 100% sure though
Answer:
Value of stamp collection = (45b + 43) cents
Step-by-step explanation:
What we have here is as follows;
if there are x 3-cent stamps, then there are 4x 10-cent stamps
So the number of 2-cent stamps is 1 less than 3 cent stamps and that will be x-1 2 cent stamps
Number of 2 cents stamps = b
This means that x-1 = b
Thus, x = b + 1
So the value of the stamp collection is as follows;
x 3 cents stamps = 3(b+ 1) = 3b + 3 cents
4x 10 cents stamps = 10(4(b + 1)) = 10(4b + 4) = 40b + 40
value of the 2 cents stamp = 2b cents
Total value is thus;
2b + 40b + 40 + 3b + 3 = (45b + 43) cents
Ummm we can't answer that question if there isn't a question , but if you are bored I understand why you put that ^-^
Answer:
8. 504ft²
9. 4970yd² (rounded to 3 s.f.)
Formulas (For easy reference):
Area of rectangle = length × breadth
Area of circle = pi×r×r
Circumference of circle = pi×r×2
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Step-by-step explanation:
8. You know a box has 6 sides, and there are 3 types of surfaces that are different from each other, and you have to multiply each side by 2 cus there are the front and backside (You can draw the box with its dimensions to see the 3 types of surfaces and why I multiplied by 2):
(2×12×6) + (2×12×10) + (2×6×10) = 144 + 240 + 120
= 504ft²
9. The net of a cylinder contains two circles of radius 24yd and one long sheet to wrap around the circles with the length that is the circumference of the circle (so that it can wrap around the two circles) and a width which is the height of the cylinder (9yd).
2 Circles = 2×pi×24×24
= 1152pi
Long sheet = 9×24×2×pi
= 432pi
Now we can add all of them together:
432pi+1152pi = 1584pi
= 4970yd² (rounded to 3 s.f.)
