The answer will be that out of 36 boys 24 speak french and 12 speak german and out of 24 girls 16 speak french and 8 speak german.
<h3>What is the frequency tree?</h3>
In the question we have that there are 60 students in total out of which 36 are boys:
So number of the girls will be = 60-36=24
Now if 2/3 of the boys speak french the number of the boys who speak french will be = (2÷3)x36=24
Now the number of the boys who speak german will be =36-24=12
Now since 40 students study french so we have the number of the boys who speak french is 24. so the number if the girls who speak french will be =40-24=16
Since there are 24 girls in total and out of them 16 speak french so the remaining girls speak german=24-16=8
Hence answer will be that out of 36 boys 24 speak french and 12 speak german and out of 24 girls 16 speak french and 8 speak german.
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Answer:
11 1/2 aka D
Step-by-step explanation:
add 7 and 4 which is 11, then add 1/4 and 1/4 which is 1/2
Answer:
Step-by-step explanation:
The mean SAT score is 
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it 
) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by 
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
In finding this value you average lower and upper bound
(0.6+0.82)/2 = 0.71
=0.71 estimated
margin of error = distance from estimate point lower/ upper bound
This interval will be twice margin error
(0.82-0.6)/2 = 0.11
How far is 0.82 from 0.71 ??
=0.11=11%
Answer: True
Step-by-step explanation:
We can simplify each of the expressions on either side to see if they are equal.
Left side: -5+7=7-5= 2
Right side: 7+-5=7-5= 2
Yes, they are equal.
