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Mathematics

1 answer:

zhenek [66]2 years ago

5 0

Answer = 7234.6 cm cu.
Reason
Volume of sphere
V= 4/3 x TT x r^3
V = 4/3 x 3.14 x 12^3
V= 7234.56
Rounded to 7234.6

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Hermes says that the opposite of 9 is 9 since

wel

Answer: Hermès is incorrect. The opposite of 9 is -9.

Explanation: In this question, Hermès gives an incorrect answer, claiming that the opposite of 9 is also 9. To find the correct answer, let’s first look at his reasoning. He was right in one thing- to find the opposite of a number, we need to find one that shares the same distance from zero. However, he was wrong in believing that the number had to be exactly the same. To find the opposite number, find the same distance from zero in the opposite direction. In this case, the distance from zero is 9. Go in the opposite direction from zero, 9 times. This would give you an answer of -9. Because of this, the opposite of 9 is -9.

Hope this helps! Comment below for more questions.

3 0

3 years ago

Tom jogged 3/7 mile on monday and 2/6 mile om Tuesday.how much farther did Tom jog on monday than Tuesday

Volgvan

3/7 (0.428571) Miles on Monday

2/6 = 1/3 (.333333) Miles on Tuesday

Subtract both numbers

.428571 - .333333 +

[Answer]: 0.095238

or 2/21 More miles on Monday.

5 0

3 years ago

All I need to know is the answer to number one.

zysi [14]

If the number is negative than it is less than it's absolute value.

4 0

3 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

<u>Trigonometric Identities</u>

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

<u>Trigonometric ratios</u>

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$