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Alborosie
2 years ago
10

Need a little help!

Mathematics
1 answer:
zhenek [66]2 years ago
5 0
Answer = 7234.6 cm cu.
Reason
Volume of sphere
V= 4/3 x TT x r^3
V = 4/3 x 3.14 x 12^3
V= 7234.56
Rounded to 7234.6
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I need help on this question, thx and i will give brainliest to the first answer that's correct.
tensa zangetsu [6.8K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
2 years ago
Read 2 more answers
The formula that describes an objects motion is given by s=ut+1/2at^2, where s is the distance traveled, u is the initial veloci
attashe74 [19]
We have the following equation:
 s = ut + 1 / 2at ^ 2
 Clear a for the equation:
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 Rewriting:
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 Answer:
 
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C. 2s-2ut / t ^ 2
6 0
3 years ago
What is the measure of the other angle?
Snowcat [4.5K]

Answer:

Try 30 degrees

Step-by-step explanation:

Because 60 degrees is half of 30 degrees

4 0
3 years ago
Read 2 more answers
A standard six-sided die is rolled twice and the top faces are observed. What is the probability that the sum of the numbers on
melisa1 [442]

<u>Answer: </u>

A standard six-sided die is rolled twice and the top faces are observed and the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

<u>Solution: </u>

The sample space of two dice outcomes is given as follows:

{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2,2) (2,3) (2,4) (2,5) (2,6)

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(5, 1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6, 1) (6,2) (6,3) (6,4) (6,5) (6,6) }

Total number of events n(s) = 36

Expected Outcomes = {(4, 6), (5, 5), (6, 4)}

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Therefore the probability that the sum of the numbers on the top faces is 10 is \frac{1}{12}

3 0
3 years ago
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