Answer:
<em>Option C</em>
Step-by-step explanation:
Consider each of these graphs. Let us formulate an inequality for each of them, and match the one with an inequality of
;
![Graph 1, x > 13.5\\Graph 2, x \geq 14\\Graph 3, x > 14.5\\Graph 4, x \geq 15](https://tex.z-dn.net/?f=Graph%201%2C%20x%20%3E%2013.5%5C%5CGraph%202%2C%20x%20%5Cgeq%2014%5C%5CGraph%203%2C%20x%20%3E%2014.5%5C%5CGraph%204%2C%20x%20%5Cgeq%2015)
Graph 3 is the only one that matches with the inequality provided to us.
* Note that shaded circles are represented by a greater / less than or equal to, and non - shaded circles are represented by a greater / less than sign.
<em>Solution ⇒ Graph 3</em>
Answer:
-1/2
Step-by-step explanation:
Answer:
First option and Fourth option.
Step-by-step explanation:
To solve this exercise you need to use the following Trigonometric Identity:
![sin\alpha=\frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=sin%5Calpha%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D)
In this case you know that:
![\alpha =C](https://tex.z-dn.net/?f=%5Calpha%20%3DC)
Since triangle ABC is similar to triangle DEF:
![\angle C=\angle F](https://tex.z-dn.net/?f=%5Cangle%20C%3D%5Cangle%20F)
Let's begin with the triangle ABC.
You can identify that:
![opposite=AB\\hypotenuse=AC](https://tex.z-dn.net/?f=opposite%3DAB%5C%5Chypotenuse%3DAC)
Then, substituing values, you get:
![sinC=\frac{AB}{AC}](https://tex.z-dn.net/?f=sinC%3D%5Cfrac%7BAB%7D%7BAC%7D)
In triangle DEF, you know that:
![opposite=DE\\hypotenuse=DF](https://tex.z-dn.net/?f=opposite%3DDE%5C%5Chypotenuse%3DDF)
So, substituing values, you get:
![sinF=sinC=\frac{DE}{DF}](https://tex.z-dn.net/?f=sinF%3DsinC%3D%5Cfrac%7BDE%7D%7BDF%7D)
To solve for c, you divide both sides by -18. If you do that, your answer will be -1/16. So, I think you typed the question wrong. Pretty sure it's the first option.