Answer:
what is ur question exactly, ur question is missing some parts
2 nuumbers multiply to 8 an addd to 6
factor 8 and add teh factor pairs
1,8
2,4
8+1=9
2+4=6
numbers are 2 and 4
if you were to solve it the
xy=8
x+y=6
y=6-x
x(6-x)=8
6x-x^2=0
0=x^2-6x+8
facotr
0=(x-2)(x-4)
set each to zero
x-2=0
x=2
x-4=0
x=4
x=2 or 4 and since they are interchangable, the numbes are 2 and 4
