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2 years ago

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A pulley is used to pull a boat to the dock. The rope is attached to the boat 7 feet below the level of the pulley. What is the

distance from the boat to the dock when the rope is 25 feet long?

1 answer:

Svetradugi [14.3K]2 years ago

7 0

Answer: 24 ft

Step-by-step explanation:

By the Pythagorean theorem,

$7^{2}+x^{2}=25^{2} \\ \\ 49+x^{2}=625 \\ \\ x^{2}=576 \\ \\ x=\boxed{24 \text{ ft}}$

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260 years equals:

uranmaximum [27]

It would have to be letter D my guy, if you know what centuries and decades are this is easy

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3 years ago

Read 2 more answers

A container manufacturer plans to make rectangular boxes whose bottom and top measure 4x by 3x. The container must contain 48in.

alex41 [277]

The height of the container that will be able to minimize the cost will be 3.08cm.

<h3>How to calculate the height?</h3>

The volume of the box will be:

= (3x)(4x)h

= 12x²h

From the information given, we are told that the container must contain 48in³. Therefore,

48 = 12x²h

h = 4/x²

The function cost will be:

= 3.50(2)(12x²) + 4.40(14x)h

= 84x² + 61.6x(4/x²)

= 84x² + 246.4/x

We'll use the first derivative. This will be:

dC/dx = 168x - 246.4/x²

x = 1.14.

Therefore, the height will be:

h = 4/x² = 4/1.14² = 3.08cm

In conclusion, the height is 3.08cm.

Learn more about height on:

brainly.com/question/1557718

4 0

2 years ago

A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are

Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that $p = 0.75$ , and four games means that $n = 4$

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164$

0.3164 = 31.64% probability the team wins all its conference games

4 0

3 years ago

A ball is dropped from a certain height. The function below represents the height f(n), in feet, to which the ball bounces at th

natali 33 [55]

Answer:

9 represents the initial height from which the ball was dropped

Step-by-step explanation:

Bouncing of a ball can be expressed by a Geometric Progression. The function for the given scenario is:

$f(n)=9(0.7)^{n}$

The general formula for the geometric progression modelling this scenario is:

$f(n)=f_{0}(r)^{n}$

Here,

$f_{0}$ represents the initial height i.e. the height from which the object was dropped.

r represents the percentage the object covers with respect to the previous bounce.

Comparing the given scenario with general equation, we can write:

$f_{0}$ = 9

r = 0.7 = 70%

i.e. the ball was dropped from the height of 9 feet initially and it bounces back to 70% of its previous height every time.

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3 years ago

Determine the marginal distribution of Gender. In paragraph form, how you calculated the marginal distribution. Include your cal

Furkat [3]

The marginal distribution for gender tells you the probability that a randomly selected person taken from this sample is either male or female, regardless of their blood type.

In this case, we have total sample size of 714 people. Of these, 379 are male and 335 are female. Then the marginal probability mass function would be

$\mathrm{Pr}[G = g] = \begin{cases} \dfrac{379}{714} \approx 0.5308 & \text{if }g = \text{male} \\\\ \dfrac{335}{714} \approx 0.4692 & \text{if } g = \text{female} \\\\ 0 & \text{otherwise} \end{cases}$

where G is a random variable taking on one of two values (male or female).

6 0

2 years ago