Answer:
The ratio of the area of ∆ABC to the area of ∆DEF is 25/36
Step-by-step explanation:
∆ABC ~∆DEF
∆ABC has a heights of 20 inches, and ∆DEF has a height of 24 inches
The ratio of the height (h1) of ∆ABC to the height (h2) of ∆DEF is:
h1 / h2= (20 inches) / (24 inches)
h1 / h2= 20 / 24
Simplifying the fraction dividing the numerator and the denominator by 4:
h1 / h2= (20/4) / (24/4)
h1 / h2= 5 / 6
The ratio of the area (A1) of ∆ABC to the area (A2) of ∆DEF is:
A1 / A2 = (h1 / h2)^2
A1 / A2 = (5 / 6)^2
A1 / A2 = 5^2 / 6^2
A1 / A2 = 25 / 36
Jimmy will receive -18 marks in the mathematics competition.
3*10=30
-8*6=-48
30+-48=-18
Hey there!
FIrstly, we have to distribute
Combine like terms
Solve for your answer
Answer: 
Good luck on your assignment and enjoy your day!
~
Answer:
its d
Step-by-step explanation:
5 times 20=100 which is d
