The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:
<h3>How to write the polynomial?</h3>
A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:
Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.
Then this polynomial is equal to:
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Answer:
The equation of required line is:
Step-by-step explanation:
We need to write equation in the form Ax+By+C=0 of the line parallel to and through the point (-2,3)
First we need to find slope and y-intercept of the required line.
Using equation of line to find slope.
Since the given line and required lines are parallel there slope is same.
Writing equation in slope intercept form: where m is slope.
So, the slope m = 5/8
The slope of required line is
Now finding y-intercept using slope and point(-2,3)
So, the equation of required line having slope and y-intercept
So, The equation of required line is: