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olga nikolaevna [1]
3 years ago
5

How is the area of a polygon defined?

Mathematics
2 answers:
love history [14]3 years ago
5 0

Answer:

This simple formula: area = 1/2 x perimeter x apothem.

It means: Perimeter × the sum of the lengths of all the sides.

Hope it helps!<3

postnew [5]3 years ago
4 0

Answer:

The surface of the polygon is the total space or area that is limited by the borders of the polygon.

Step-by-step explanation:

This area is the amount of space limited by the borderlines and occupied by a polygon. By definition, the sides of the polygon are the same in size. The area of any polygon can be defined by dividing the polygon into triangles.

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Which of the following inequalities are true
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3 years ago
Please help!
crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

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2 years ago
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Answer:

Halfway 8787

Step-by-step explanation:

Okay man so wouwiw r Kelly 888999

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(Feet per minute) x (number of minutes)

20x5 = 100
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