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Whitepunk [10]
2 years ago
14

According to coulomb's law, rank the interactions between charged particles from highest potential energy to lowest potential en

ergy.rank from highest to lowest potential energy. to rank items as equivalent, overlap them.1. 1+ charge and 1- charge seperated by 200pm2. 1+ charge and 1+ charge seperated by 100pm3. 1+ charge and 1- charge seperated by 100pm4. 2+ charge and 1- charge seperated by 100pm
Physics
1 answer:
Taya2010 [7]2 years ago
8 0

Answer: (2) > (1) > (3) > (4)

Explanation:

(1) a +1 charge and a -1 charge separated by 200 pm:

The potential energy in this case will be,

U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+1 \ C)(-1 \ C)}{200 \times 10^{-9} \ m } \\ & = - \frac{1}{2}k \times 10^7 \ \rm J

(2) a +1 charge and a +1 charge separated by 100 pm:

The potential energy in this case will be,

U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+1 \ C)(+1\ C)}{100 \times 10^{-9} \ m } \\ & = k \times 10^7 \ \rm J

(3) a +1 charge and a -1 charge separated by 100 pm:

The potential energy in this case will be,

U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+1 \ C)(-1 \ C)}{100 \times 10^{-9} \ m } \\ & = - k \times 10^7 \ \rm J

(4) a +2 charge and a -1 charge separated by 100 pm:

The potential energy in this case will be,

U_E & = k\;\rm (N\cdot m^2/C^2) \dfrac{(+2 \ C)(-1 \ C)}{100 \times 10^{-9} \ m } \\ & = - 2k \times 10^7 \ \rm J

So, the order from <u>highest</u> potential energy <u>to lowest</u> potential energy is:

(2) > (1) > (3) > (4)

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