Answer:
The temperature change per compression stroke is 32.48°.
Explanation:
Given that,
Angular frequency = 150 rpm
Stroke = 2.00 mol
Initial temperature = 390 K
Supplied power = -7.9 kW
Rate of heat = -1.1 kW
We need to calculate the time for compressor
Using formula of compression



Put the value into the formula


We need to calculate the rate of internal energy
Using first law of thermodynamics


Put the value into the formula


We need to calculate the temperature change per compression stroke
Using formula of rate of internal energy


Put the value into the formula


Hence, The temperature change per compression stroke is 32.48°.
Answer:
thermoset
Explanation:
A thermoset material is a polymer that is irreversibly hardened by curing. Curing is induced by heat and cannot be undone because the polymers cross link during the process, creating permanent chemical bonds.
Explanation:
Force is applied to lift a body against the force of gravity. Example: If an object is lifted to a certain height (h)
Answer:
x(t) = -8sin2t
Explanation:
See the attachment for solution
From my solving, we can deduce that w² = 4, and thus, w = 2
Therefore, the general solution is
x(t) = c1 cos2t + c2 sin2t
Considering the final variable, we can conclude that
x(0) = 0
x'(0) = -8 m/s
The final solution, thus
x(t) = -8sin2t
Answer:
v = 7.69 x 10³ m/s = 7690 m/s
T = 5500 s = 91.67 min = 1.53 h
Explanation:
In order for the satellite to orbit the earth, the force of gravitation on satellite must be equal to the centripetal force acting on it:

where,
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
Me = Mass of Earth = 5.97 x 10²⁴ kg
r = distance between the center of Earth and Satellite = Radius of Earth + Altitude = 6.371 x 10⁶ m + 0.361 x 10⁶ m = 6.732 x 10⁶ m
v = orbital speed = ?
Therefore,

<u>v = 7.69 x 10³ m/s</u>
For time period satellite completes one revolution around the earth. It means that the distance covered by satellite is equal to circumference of circle at the given altitude.
So, its orbital speed can be given as:

where,
T = Time Period of Satellite = ?
Therefore,

<u>T = 5500 s = 91.67 min = 1.53 h</u>