Hello,
Answer C triangle isocele
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Step-by-step explanation:
Ok. First of all, we need to follow the order of operations: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. We don't have any parentheses, exponents, or division to resolve, so you can skip those. So now you have: Multiplication, Addition, and Subtraction. We have multiplication in each term, but each term is fully simplified, so we have Addition and Subtraction left.
With that out of the way, let's go ahead and rearrange this equation so it is easier to solve. (<em>Note: we can only rearrange terms that are positive because subtraction is not commutative. But we can turn negative terms into "positive" terms by the method shown below.</em>)
4a - 7b + 2ab - a + b
4a + (-7b) + 2ab + (-a) + b (<em>Now the terms are all positive, so we can rearrange them, but they still have the same value.</em>)
4a + (-a) + 2ab + (-7b) + b
3a + 2ab + 7b
And there we go. Our answer is fully simplified. If you can understand this, you'll be able to simplify without isolating and rearranging the terms each time.
Hopefully this was helpful and not confusing.
Answer:
D.) 0.9990
Step-by-step explanation:
Given :
Number of questions = 10
True or False questions ; probability of success, p = 1/2 = 0.5
Using binomial distribution :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
Probability of getting atleast one correct answer :
P(x ≥ 1) = p(1) + p(2) +... P(x = 10)
Using a binomial probability calculator :
P(x ≥ 1) = 0.9990
Answer:
Option (B)
Step-by-step explanation:
The given question is incomplete; here is the complete question.
The radius of a circle is 6. Using π, which equation expresses the ratio of the circumference of the circle to the circle's diameter?
A) C/6 = π
B) C/12= π
C) C = 6πr
D) C = 12πr
Formula to get the circumference of the circle is,
C = 2πr = π × D
Where C = circumference of the circle
D = Diameter of the circle
By dividing with D on both the sides of the formula,
Since, diameter 'D' = 2r,
Therefore, equation given in Option (B) will be the correct expression.
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