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marissa [1.9K]
2 years ago
12

Help please, I suck at maths

Mathematics
2 answers:
Kazeer [188]2 years ago
7 0

Answer:1, 5

Step-by-step explanation:

divide the expression to get your answer then divide the choices on the right. find the ones with the same answer.

castortr0y [4]2 years ago
7 0

Answer:

7,610/50

.761/.005

Step-by-step explanation:

Compare both expressions' sums and check them off.

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Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin
34kurt

Answer:

                \dfrac{1}{30}

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

1•1•4•3 = 12

The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}

7 0
3 years ago
The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
likoan [24]

Answer:

A)  3%

B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
  • b = 1.01
  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

4 0
2 years ago
6x44<br> hbgvtfwtydtwftdftwyfdywdwd
Ipatiy [6.2K]

Answer:

264

Step-by-step explanation:

well you could have just used a calculator!

3 0
2 years ago
Read 2 more answers
The___ of an angle is the ratio of the opposite leg length to the hypotenuse length.
ozzi
The answer would be sine
7 0
2 years ago
Read 2 more answers
If p is a point with polar coordinates ​(r,thetaθ​), the rectangular coordinates​ (x,y) of p are given by xequals=​_______ and y
Anuta_ua [19.1K]

Answer:

x = r cos theta and y = r sin theta

Step-by-step explanation:

cos theta = x / r  so:-

x = r cos theta

and sin theta = y / r, so

y =  r sin theta

5 0
3 years ago
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