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Strike441 [17]
3 years ago
15

Marco's family is renting a cabin by the lake. The cost is $40 per day plus a one-time cleaning fee of $60. How many whole days

can the family stay, if they have budgeted a maximum of $275 for the cabin? What is the variable for this situation? ​
Mathematics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Cost per day = 40

Cleaning fee = 60

Budget = 275

Total cost for one day = 100

The family can stay two whole days

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ankoles [38]
Ratio and proportion

height:shadow=1.5:2

for the building, shadow=24

1.5:2=h:24
1.5/2=h/24
multiply both sides by 24
36/2=h
18=h
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3 years ago
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Help please!<br><br> A.<br><br><br> B.<br><br><br> C.<br><br><br> D.
elixir [45]

Answer:

D.

b = 175; which is the initial # of pages to start

Step-by-step explanation:

you can find the slope to find b or y-intercept (x=0) for equation

y=mx+b

to find m = (y2-y1)/(x2-x1)

(x1,y1) = (9, 100)

(x2, y2) = (15, 50)

m = (50-100) / (15-9) = -50/6 = -25/3

let use point (15, 50)

y=mx+b

50 = -25/3*x + b

50 = (-25/3)*(15) + b

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3 years ago
Factor 3x^2 - 14x + 8​
atroni [7]

Answer: (3x- 2)(x-4)

Factor by grouping.

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Write as a product: 25a2−0.01b10
Yakvenalex [24]

Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

so

25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

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Therefore, we conclude that:

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