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4 years ago

The equation 3/4 [x-1]=[-3] is equivalent to?

Mathematics

1 answer:

olga nikolaevna [1]4 years ago

3 0

Answer: x= (-3)

Step-by-step explanation:

3/4 [x-1] = [-3]

(x-1) = (-3) × 4/3

X-1 = -4

X= -3

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(1 point)

Rashid [163]

The third one is the answer for this question

3 0

3 years ago

WILL GIVE BRAINLIEST

tiny-mole [99]

The expressions for each of the given statements are

a. 6 + z

b. 20 - x

c. x/6 - 8

d. x + 5/4

<h3>Writing an expression </h3>

From the question, we are to write an expression for each of the given statement

a. the sum of 6 and z

That is,

6 + z

b. the difference between 20 and x

That is,

20 - x

c. 8 less than the quotient of x divided by 6

That is,

x/6 - 8

d. x increased by 5 divided by 4

That is,

x + 5/4

Hence, the expressions for each of the given statements are

a. 6 + z

b. 20 - x

c. x/6 - 8

d. x + 5/4

Learn more on Writing an expression here: brainly.com/question/17651563

#SPJ1

4 0

2 years ago

What do you think about when you hear the phrase "system of equations"? In other words, what do you already know about systems o

Reptile [31]

Basically the question is asking YOU when you hear “system of equations” what do you think about it - what do you already know about system of equations. Basically. Btw enjoy this picture.

4 0

3 years ago

Find the perimeter of the triangle with vertices A(negative 2,2,3), B(4,negative 4,3), and C(7,6,4).

gayaneshka [121]

Answer:

$P\approx 28.872\,\text{units}$

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

for the side AB: A(-2,2,3) and B(4,-4,3)

$AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}$

$AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}$

$AB = \sqrt{72}$

for the side BC: B(4,-4,3) and C(7,6,4)

$BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}$

$BC = \sqrt{110}$

for the side CA: C(7,6,4) and A(-2,2,3)

$CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}$

$CA = \sqrt{98}$

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

$P = AB + BC + CA$

$P = \sqrt{72} + \sqrt{110} + \sqrt{98}$

$P\approx 28.872\,\text{units}$

this is the perimeter of triangle ABC

6 0

4 years ago

Write an equation of the line below

gregori [183]

Answer:

The equation of the line is:

$y = 4x + 3$

Step-by-step explanation:

We know that the slope-intercept of line equation is

$y = mx+b$

Where m is the slope and b is the y-intercept

Given the two points on a line

(0, 3)

(-2, -5)

Finding the slope between (0, 3) and (-2, -5)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(0,\:3\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-5\right)$

$m=\frac{-5-3}{-2-0}$

$m=4$

We know that the y-intercept can be computed by setting x=0 and determining the corresponding y-value.

From the graph, it is clear:

at x = 0, y = 3

Thus, y-intercept = b = 3

Substituting m = 4 and b = 3 in the slope-intercept form of line equation

$y = mx+b$

$y = 4x + 3$

Therefore, the equation of the line is:

$y = 4x + 3$

8 0

3 years ago