Answer:
#include <stdio.h>
int fib(int n) {
if (n <= 0) {
return 0;
}
if (n <= 2) {
return 1;
}
return fib(n-1) + fib(n-2);
}
int main(void) {
for(int nr=0; nr<=20; nr++)
printf("Fibonacci %d is %d\n", nr, fib(nr) );
return 0;
}
Explanation:
The code is a literal translation of the definition using a recursive function.
The recursive function is not per se a very efficient one.
Answer:
focuses on how to design, integrate, and manage complex systems over their life cycles
Answer:
ohhh ok to all transactions.
Answer:
def wordsOfFreqency(words, freq):
text1 = "Apple apPLE mangO aPple orange Orange apple guava Mango mango"
words = []
words1 = []
words1 = text1.split()
words = [x.upper() for x in words1]
freq=[words.count(w) for w in words]
print(dict(zip(freq,words)))
return words
def main():
wordsOfFreqency(words, freq)
if __name__=="__main__":
main() # call main function
Explanation:
This will print the list of strings as per its word frequency.
Output is :
{4: 'APPLE', 3: 'MANGO', 2: 'ORANGE', 1: 'GUAVA'}
Because they will change their identity and therefore they will never have the same name for a long period of time . So when they commit a crime , they will be difficult to find and catch
