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solmaris [256]
2 years ago
14

What is the length of the hypotenuse? If necessary, round to the nearest tenth.

Mathematics
1 answer:
azamat2 years ago
4 0

By the Pythagorean theorem,

a^{2}+12^{2}=13^{2}\\\\a^{2}+144=169\\\\a^{2}=25\\ \\ a=\boxed{5}

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11y^2-19y-10=-4y^2 <br> all real solutions
tangare [24]

Answer:

y=5/3 is the only real solution

Step-by-step explanation:

Solve for y over the real numbers:

11 y^2 - 19 y - 10 = -4 y^2

Add 4 y^2 to both sides:

15 y^2 - 19 y - 10 = 0

The left hand side factors into a product with two terms:

(3 y - 5) (5 y + 2) = 0

Split into two equations:

3 y - 5 = 0 or 5 y + 2 = 0

Add 5 to both sides:

3 y = 5 or 5 y + 2 = 0

Divide both sides by 3:

y = 5/3 or 5 y + 2 = 0

Subtract 2 from both sides:

y = 5/3 or 5 y = -2

Divide both sides by 5:

Answer: |

| y = 5/3 or y = -2/5

4 0
3 years ago
Which binomial is a factor of 49x2 + 84 xy + 36y2?
bezimeni [28]

Answer:

(7x+6y) is a binomial factor of the given expression  49x^2+84xy+36y^2

Therefore  49x^2+84xy+36y^2=(7x+6y)(7x+6y)

Step-by-step explanation:

Given expression is 49x^2+84xy+36y^2

To find the binomial factor :

49x^2+84xy+36y^2

Rewritting the above expression as

=7^2x^2+2(7)(6)xy+6^2y^2

=(7x)^2+2(7x)(6y)+(6y)^2

=(7x+6y)^2 ( using the formula =(a+b)^2=a^2+2ab+b^2 here a=7x and y=6y )

=(7x+6y)(7x+6y) ( using the formula =(a+b)^2=(a+b)(a+b) )

Therefore  49x^2+84xy+36y^2=(7x+6y)(7x+6y)

(7x+6y) is a binomial factor of the given expression  49x^2+84xy+36y^2

7 0
3 years ago
Round 1199.28856995 to the nearest ten,
Wittaler [7]

1199.3 (I'm assuming you mean round to the nearest tenth)

5 0
3 years ago
Statistics help please!!!
Andre45 [30]

Answer:

see i have posted my pic

Step-by-step explanation:

please mark me as brainliest

8 0
3 years ago
The difference of two numbers is 33. The sum of the first number and four times the second number is -2. What is the larger of t
defon

Answer:

The larger of the two is 44.67

Step-by-step explanation:

let the first number=x

let the second number=y

We can derive a system of equations using the mathematical statements

Their sum is 33:

x+y=33( call this equation 1)

Sum of first number and four times the second is -2:

x+4y=-2(call this equation 2)

Since the integer coefficients of x in both equations are the same we can quickly subtract one from the other to eliminate it

For this explanation, I choose to subtract equation 1 from 2

(x+4y=-2)-(x+y=33)=3y=-35

y=-35/3

Now plug in the value of y into any equation for that of x. Say we plug into equation 1

x+(-35/3)=33

x-35/3=33( multiply through by 3)

3x-35=99

3x=99+35

3x=134

x=134/3

Therefore,x=134/3 or 44.67 and y=-35/3 or -11.67

7 0
3 years ago
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