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saul85 [17]
2 years ago
7

7^x=3^[x+4] solve x using logarithmic

Mathematics
1 answer:
Andrei [34K]2 years ago
4 0

By taking advantage of the definition of <em>exponential</em> and <em>logarithmic</em> function and their inherent relationship we conclude that the solution is x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3).

<h3>How to solve an exponential equation by logarithms</h3>

<em>Exponential</em> and <em>logarithmic</em> functions are <em>trascendental</em> functions, these are, functions that cannot be described <em>algebraically</em>. In addition, <em>logarithmic</em> functions are the <em>inverse</em> form of <em>exponential</em> functions. In this question we take advantage of this fact to solve a given expression:

  1. 7ˣ = 3ˣ⁺⁴     Given
  2. ㏒ 7ˣ = ㏒ 3ˣ⁺⁴      Definition of logarithm
  3. x · ㏒ 7 = (x + 4) · ㏒ 3     ㏒ aᵇ = b · ㏒ a
  4. x · ㏒ 7 = x · ㏒ 3 + 4 · ㏒ 3     Distributive property
  5. x · (㏒ 7 - ㏒ 3) = 4 · ㏒ 3      Existence of additive inverse/Modulative and associative properties
  6. x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3)     Existence of multiplicative inverse/Modulative property/Result

By taking advantage of the definition of <em>exponential</em> and <em>logarithmic</em> function and their inherent relationship we conclude that the solution is x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3).

To learn more on logarithms: brainly.com/question/20785664

#SPJ1

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