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yaroslaw [1]
3 years ago
14

The average score of all golfers for a particular course has a mean of 70and a standard deviation of 5.Suppose 100golfers played

the course today. Find the probability that the average score of the 100golfers exceeded 71.Round to four decimal places.
Mathematics
1 answer:
Schach [20]3 years ago
6 0

Answer:

0.9773

Step-by-step explanation:

Here, we start by calculating the z-scores statistic

Mathematically;

z-score = (x-mean)/SD/√n

From the question, we have;

x = 71, mean = 70, SD = 5 and n = 100

Plugging these values in the equation above, we have;

z-score = (71-70)/5/√100 = 1/5/10 = 1/0.5 = 2

So the probability we want to calculate is that;

P(z > 2)

This is obtainable from the standard normal distribution table

P(z > 2) = 0.97725 which is 0.9773 to 4 decimal places

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Please answer all part correct​
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Answer:

a). We want to know how much each point was worth.

b). 12x+5=41

c). Each problem worth 3 points.

Step-by-step explanation:

a). We want to know how much each problem was worth. Because we have the total points of the test, and how much was the bonus. But we still don't know the worth of each problem.

b). We know that the total points of the test were 41, and the bonus 5 points. There were 12 problems on the test and we are going to use "x" for the unknown part (how many points each problem was worth).

The equation is :

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Why 12x? Because if you multiply the twelve problems of the test with the worth of each one and then add the 5 points of the bonus you will obtain the total points of the test (41).

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Subtract 5 from both sides.

12x+5-5=41-5\\12x=36

Finally divide in 12 both sides of the equation:

\frac{12x}{12}=\frac{36}{12} \\\\x=3

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