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1 year ago

15

NEED HELP ASAP!!!!!

1 answer:

Law Incorporation [45]1 year ago

3 0

Answer:the length 7

Step-by-step explanation:each one is times 3 6x3 8x3 3x7=21

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I need help with the question above

Neporo4naja [7]

2a/5b = 6

(2a-5b)/5b could be written as: (2a/5b) -(5b/5b)

Repace by its equivalent value (6) -(1) = 5

4 0

2 years ago

Specialty t-shirts are being sold online for $15 each, plus a one-time

kolbaska11 [484]

I think it’s A sorry if I’m wrong:)

8 0

2 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago

In the figure, GK bisects FGH

bija089 [108]

Answer:

$w = 7$

Step-by-step explanation:

Given:

m<FGK = (7w + 3)°

m<FGH = 104°

angle bisector of <FGH = GK

Required:

Value of w

SOLUTION:

Since GK bisects angle FGH, it divides the angle into two equal parts. Therefore, the following equation can be generated to find the value of w:

m<FGH = 2*m<FGK

$104 = 2*(7w + 3)$ (substitution)

Divide both sides by 2

$\frac{104}{2} = \frac{2*(7w + 3)}{2}$

$52 = 7w + 3$

Subtract 3 from each side

$52 - 3 = 7w + 3 - 3$

$49 = 7w$

Divide both sides by 7

$\frac{49}{7} = \frac{7w}{7}$

$7 = w$

$w = 7$

8 0

3 years ago

Please help mee

NemiM [27]

(2^6)^x=1
(4)^x=1
(4)^0=1
1=1
X=0

(5^0)^x=1
(1)^x=1
x=(-∞,∞)

5 0

2 years ago