Complete question is;
A model for a company's revenue from selling a software package is R = -2.5p² + 500p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue.
Answer:
Price to maximize revenue = $100
Maximum revenue = $25000
Step-by-step explanation:
We are told that:
R = -2.5p² + 500p, where p is the price in dollars of the software.
The maximum revenue will occur at the vertex of the parabola.
Thus, the price at this vertex is;
p = -b/2a
Where a = - 2.5 and b = 500
Thus:
p = -500/(2 × -2.5)
p = -500/-5
p = 100 in dollars
Maximum revenue at this price is;
R(100) = -2.5(100)² + 500(100)
R(100) = -25000 + 50000
R(100) = $25000
The difference quotient is -6. See photo for the work.
P is equal to plus or minus 2 because it'll both be equal to 4
Answer:
It is graph C
Step-by-step explanation:
I can not set up a 2 way table online but what they want is a collom of the information neatly laid out...
With the 9th graders in one collom and the 10th graders in the other
like this
9th grader 10th grader
# of students 32 40
# of participated 32 18
Draw this out with lines and it will be correct.
I hope this helps GOOD LUCK...this is tough math for a middle schooler.
