Maximum time allowed = 7 deg. / 0.03 deg/s = 233.3 s
Minimum speed = 55 yd * 3 ft/yd / 233.3 s
= 0.707 ft/s
Answer:
The distance would be 4 units and you would go 4 to the right
I hope this helps :)
Step-by-step explanation:
Answer:
your answer will be C. B´C=8. m ZA=28
Step-by-step explanation:
hope it helps have a nice day
Answer:
6 jellybean
Step-by-step explanation:
Given that:
Esmeralda received a bag of jellybean the contains regular flavored jelly beans and surprise jelly bean.
Consider the regular flavored jellybean to be = r; &
The surprise jelly bean.= s
From the bag, there are 40 jellybeans of which 15% is surprise jellybean.
Therefore the number of expected surprise jellybeans is:
= total number of jellybeans × percentage of surprise jellybean
= 40 × (15 /100)
= 6 jellybean
If 6 surprise jellybean is presented in the bag; then the number of regular flavored jellybean = 40 - 6 = 34 regular flavored jellybean
Orders: x
Inventory: y
1) First table
x2-x1=6-3→x2-x1=3
y2-y1=1920-1960→y2-y1=-40
x3-x2=9-6→x3-x2=3=x2-x1
y3-y2=1900-1920→y3-y2=-20 different to y2-y1=-40. The table does not represent a linear relationship.
2) Second table
x2-x1=7-5→x2-x1=2
y2-y1=1860-1900→y2-y1=-40
x3-x2=9-7→x3-x2=2=x2-x1
y3-y2=1820-1860→y3-y2=-40=y2-y1
x4-x3=11-9→x4-x3=2=x3-x2
y4-y3=1780-1820→y4-y3=-40=y3-y2
x5-x4=13-11→x5-x4=2=x4-x3
y5-y4=1740-1780→y5-y4=-40=y4-y3
The table represents a linear relationship.
3) Third table
x2-x1=2-1→x2-x1=1
y2-y1=1000-2000→y2-y1=-1000
x3-x2=3-2→x3-x2=1=x2-x1
y3-y2=500-1000→y3-y2=-500 different to y2-y1=-1000. The table does not represent a linear relationship.
4) Fourth table
x2-x1=6-4→x2-x1=2
y2-y1=1640-1840→y2-y1=-200
x3-x2=8-6→x3-x2=2=x2-x1
y3-y2=1360-1640→y3-y2=-280 different to y2-y1=-200. The table does not represent a linear relationship.
Answer: The second <span>table best represents a linear relationship.</span>
