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tresset_1 [31]
2 years ago
10

Write the contrapositive and the converse of the following conditional

Mathematics
2 answers:
Lunna [17]2 years ago
6 0

The contrapositive statement are:

  • If the lake is frozen, then it isn't cold.
  • If Solomon is happy, then  he isn't healthy.
  • If Tigist  does not take a walk, then it will not rain

<h3>What is the converse statement?</h3>

The  converse statement are:

  • If the late is frozen, then it is cold.
  • If Solomon is happy, then he is healthy.
  • If Tigist Tigist  does not take a walk, then it will rain.

Note that the converse of a statement is created by the act of switching the hypothesis given and also the conclusion.

Therefore, The contrapositive statement are

  • If the lake is frozen, then it isn't cold.
  • If Solomon is happy, then  he isn't healthy.
  • If Tigist  does not take a walk, then it will not rain

Learn more about contrapositive statement  from

brainly.com/question/1713053

#SPJ1

kenny6666 [7]2 years ago
4 0

The contrapositive statement is:

If the lake is frozen, then it isn't cold.

If Solomon is happy, then he isn't healthy.

If Tigist does not take a walk, then it will not rain.

We have given that the statements,

We have to determine the contrapositive and the converse of the following conditional statements.

<h3>What is the converse statement?</h3>

The  converse statement is:

If the late is frozen, then it is cold.

If Solomon is happy, then he is healthy.

If Tigist Tigist does not take a walk, then it will rain.

Note that the converse of a statement is created by the act of switching the hypothesis is given and also the conclusion.

Therefore, The contrapositive statement is

If the lake is frozen, then it isn't cold.

If Solomon is happy, then he isn't healthy.

If Tigist does not take a walk, then it will not rain.

Learn more about contrapositive statements from

brainly.com/question/1713053

#SPJ1

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Step-by-step explanation:

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In a trolley ride around an amusement park, a child traveled from one signpost to a second signpost at a constant speed of 125 m
Inessa05 [86]

Answer:

Given speed of trolley = 125 meters per minute

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hence depending on the given information we cannot come to any conclusion weather the distance travelled is less than 800 m or greater than 800 m.

For the second case

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Thus the distance traveled is

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An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.
lawyer [7]

Answer:

7.5cm²

Complete question:What is the surface area of the 8-sided figure?

Step-by-step explanation:

Consider the half of the 8-sided die i.e the pyramid ABCDE:

As the base is 6 of the perimeter, so each side of the base is 6/4=3/2

Now, the distance between the tallest points is 2 cm, so the height of Pyramid ABCDE is 1 cm.

Considering the right triangle EOM:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is 

\sqrt{1+ ( \frac{3}{4} )^{2} }=  \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4}   (cm)

5. So side EBC has area  

\frac{1}{2}BC*EM=  \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}

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3 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

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