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MariettaO [177]
3 years ago
12

Divide x^3 -3x^2 by x-2 . Step 2 - Fill in the missing number:

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

12

x

2

+

2

x

6

x

1

3

⋅

1

4

6

x

3

+

4

x

2

−

x

x

2

−

4

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
Can someone help me solve this problem please! I'd really appreciate it!!
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3 0
2 years ago
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Stu trained for a triathlon for 5 hours yesterday. He ran 5 miles and then biked 80 miles. His biking speed is 15 mph faster tha
lara31 [8.8K]

Answer:

Step-by-step explanation:

Given as :

The distance cover while running = D_1 = 5 miles

Let The speed for running = S_1

The distance cover with bike = D_2 = 80 miles

The speed for biking = S_2 = 15 mph +  S_1

Total Time taken = 5 hours

Now Time = \dfrac{\textrm Distance}{\textrm Speed}

∴ 5 hour = \frac{D_1}{S_1} +  \frac{D_2}{S_2}

Or,  5 hour = \frac{5}{S_1} +  \frac{80}{15+S_1}

Or, 5 hour = \frac{75 + 5 S_1 + 80 S_1}{S_1(15+S_1)}

or,  5 × (S_1^{2}+15 S_1) = 85 S_1 + 75

Or, 5 S_1^{2} + 75 S_1 -  85 S_1 - 75 = 0

or, 5 S_1^{2} -10 S_1 - 75 = 0

or,   S_1^{2} -2 S_1 - 15 = 0

Or, S_1^{2} -3 S_1 + 5 S_1- 15 = 0

Or, S_1 (S_1 - 3) + 5 (S_1 - 3) = 0

Or, (S_1 - 3) ( S_1 + 5 ) = 0

∴ S_1 = 3 , - 5

So, the running speed = 3 mile per hour

And the biking speed = 15 mph + 3 mph = 18 mile per hour

Hence The running speed of Stu is 3 mile per hour  .  Answer

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3 years ago
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Answer:

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6 0
3 years ago
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Divide 4/5 by 2/3.<br> a. 8/15b. 5/6c. 1 1/5d. 1 7/8
Ivan
4/5÷2/3=x
4/5×3/2=x
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