All categories

3 years ago

What is the value of x (x+2)(x-3)=0

Mathematics

1 answer:

wolverine [178]3 years ago

8 0

Answer:

x = 3 or x = -2

Step-by-step explanation:

Solve for x over the real numbers:

(x + 2) (x - 3) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

x - 3 = 0 or x + 2 = 0

Hint: | Look at the first equation: Solve for x.

Add 3 to both sides:

x = 3 or x + 2 = 0

Hint: | Look at the second equation: Solve for x.

Subtract 2 from both sides:

Answer: x = 3 or x = -2

You might be interested in

How to solve this problem

Pavlova-9 [17]

For this one you can use 3/8 + 3/8 since 3+3 is equals to 6 and the 8 stays as it is.
I hope this helps.
YOU'RE WELCOME :D

4 0

3 years ago

What is the slope of -2/3? WILL GIVE BRAINLIEST!!!

Nataliya [291]

Answer:

( intransitive) To tend steadily upward or downward. ...

( transitive) To form with a slope; to give an oblique or slanting direction to; to incline or slant. ...

( colloquial, usually followed by a preposition)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

The equation y=2x+3 represents the cost y (in dollars) of mailing a package that weighs x pounds. a. Graph the equation. b. Usin

FinnZ [79.3K]

Answer:

B. Slightly more than $5

Step-by-step explanation:

y = 2x + 3

Firstly we check variables to make sure we understand.

y = dollars

x = pounds

On the scale, it says 1.126 lb. Which means 1.126 pounds.

And so, x = 1.126

y = 2x + 3

y = 2(1.126) + 3

y = 2.252 + 3

y = 2.252

The graph for part a and park b. It is underneath. I wrote 1.1, because it is rounded down from 1.126 lb, which is part b. The one with one line and no dots is part a.

4 0

2 years ago

If f(x)=x^2-3 and

Kipish [7]

Since it is f of g you have to start by plugging in g(x) into f(x)

(4-3x)^2-3

Then just solve the equation

(4-3x)^2-3
(4-3x)(4-3x)-3 Square the binomial
8-12x-12x+9x^2-3 Combine like terms
5-24x+9x^2 Final answer

4 0

2 years ago